SQL and binary numbers

  • siva 20997 (3/9/2012)


    These are like Bits in a Byte being switched on or off

    AND ing with whatever (in this case 32) is the correct way

    However doing that seems to be a problem here

    However you are lucky here because any number greater than 31 is is unconfirmed because it is the higest number

    This will work as long as you do not have a 64 meaning They have gone bankrupt

    I believe you're confusing the BIT number with the value to find it. An INT contains 4 bytes and has bits 0 through 31. Each BIT can be ANDed using the power of 2 for that bit. 2^31 is 2,147,483,648.

    If you were constrained to a single byte (bits 0 through 7), the largest unsigned single bit value would be 128, not 64.

    --Jeff Moden


    RBAR is pronounced "ree-bar" and is a "Modenism" for Row-By-Agonizing-Row.
    First step towards the paradigm shift of writing Set Based code:
    ________Stop thinking about what you want to do to a ROW... think, instead, of what you want to do to a COLUMN.
    "Change is inevitable... change for the better is not".

    Helpful Links:
    How to post code problems
    How to Post Performance Problems
    Create a Tally Function (fnTally)
    Intro to Tally Tables and Functions

  • This is what he said

    Papersdue 1 ; Papers due (2^0)

    Dueflag 2 ; Due letter sent flag (2^1)

    Chaserflag 4 ; Chaser letter sent flag (2^2)

    Feesettle 8 ; Fees settlement flag (2^3)

    Statement 16 ; Statement flag (2^4)

    Unconfirmed 32 ; Unconfirmed flag (2^5)

    This is what I understand by it

    Depending on the Status a differnt number will be stored in a single field

    so fo example

    If Papersdue it will store 1

    if Due letter has been sent then it will store 2

    however if Paersdue and DueFlagHas been sent it will store 1+2=3

    So each flag has a value

    if all flags has to be set ie Papersdue,Due letter has been sent etc etc the number stored will be

    1+2+4+8+16+32 = 63

    so without the unconfirmed flag being set the rest of the numbers can not get above 31

    So I said if it is more than 31 the unconfirmed flag is set

    Now I know how to do it if it had 64 and 128 too but I wont go into that now

    People do this at byte level and it is known as masking or filtering as the CPU has a instruction set to do this I belive. Here someone has tried to do that with Integer numbers

    I have done this long time back (in dbf) when I wanted to match House buyers to houses

    depending on which boxes the purchaser ticks you work out a number

    you do the same with house beased on ots properties

    only the numbers are stored against the house and the buyer

    by going through the algoritham you can work out which houses match the purchaser

  • The OP also said he was using DECIMAL. I understand the bit values being used but I didn't want people to mistake what you said for being limited to a max value of 32 for the largest bit.

    --Jeff Moden


    RBAR is pronounced "ree-bar" and is a "Modenism" for Row-By-Agonizing-Row.
    First step towards the paradigm shift of writing Set Based code:
    ________Stop thinking about what you want to do to a ROW... think, instead, of what you want to do to a COLUMN.
    "Change is inevitable... change for the better is not".

    Helpful Links:
    How to post code problems
    How to Post Performance Problems
    Create a Tally Function (fnTally)
    Intro to Tally Tables and Functions

  • The decimal or integer doesnt matter as long as the principal is understood

    This is what he said and can be represented further (just concentrate on the number not the decimal as the decimal part is not being used.) I have extended the number to binary notaion

    Papersdue 1 ; Papers due (2^0) 00000001

    Dueflag 2 ; Due letter sent flag (2^1) 00000010

    Chaserflag 4 ; Chaser letter sent flag (2^2) 00000100

    Feesettle 8 ; Fees settlement flag (2^3) 00001000

    Statement 16 ; Statement flag (2^4) 00010000

    Unconfirmed 32 ; Unconfirmed flag (2^5) 00100000

    Bankrupt 64; Bankrupt Flag (2^6) 01000000

    TakenOver 128; Taken Over (2^7) 10000000

    So witht one byte (if it was interger) or more bytes if it was real,float we have represented 8 flags. This is how it is done when the memeorey is limited. You would see that in the computer BIOS parameters are set like that. not one byte per flag but one bit per flag

    In this case the user has wasted space by putting it into a decimal field it should have been interger field

    anyway if the unconfirmaedrmed flag is set the flags would look like this ??1????? where ? indicates that it can be 0 or 1

    So AND ing it with the 32 like ??1????? and 00100000 would give result like

    00000000 Unconfirmed flag is NOT set

    00100000 Uncofirmaed flag is set

    The fisrt answer by the Vetran was (Colname and 32)=32 was that.it should return 0 or 1. In other languages it does. the AND opertaor does that in Assembler , C , Pascal or any programming language

    but not in TSQL and I am not sure of the reasons

    So in the absence of AND operator how do you determine the 8 flags

    1) divide the number by 128 first. if the result is 1 with a reminder then the 8th flag is set

    2) divide the reminder with 64.if the result is 1 with a reminder then the 7th flag is set

    3) divide the reminder with 32.if the result is 1 with a reminder then the 6th flag is set

    That is what the AND Operator does

    The technique they have used might sound archaic but that is how bit flags are set and we use one byte to set 8 flags. he dip switches on motherboars, network cards etc have these 8 switches, they are exavtley doing what I have said above to store one byte of information

    Hope I have explained this 🙂

  • Sorry there is a & operator in SQL

    and the solution given by the vetran does work once converted to int

  • It should read

    Papersdue 1 ; Papers due (2^1) 00000001

    Dueflag 2 ; Due letter sent flag (2^2) 00000010

    Chaserflag 4 ; Chaser letter sent flag (2^3) 00000100

    Feesettle 8 ; Fees settlement flag (2^4) 00001000

    Statement 16 ; Statement flag (2^5) 00010000

    Unconfirmed 32 ; Unconfirmed flag (2^6) 00100000

    Bankrupt 64; Bankrupt Flag (2^7) 01000000

    TakenOver 128; Taken Over (2^8) 10000000

    I was hasty and made the mistake

    Good that I didnt go into teaching proffesion

  • siva 20997 (3/10/2012)


    That is what the AND Operator does

    Just to be clear... AND does no form of division. You may be able to emulate it with division but I don't want people to walk away from this thread thinking that AND uses division in any way, shape or form because it doesn't.

    --Jeff Moden


    RBAR is pronounced "ree-bar" and is a "Modenism" for Row-By-Agonizing-Row.
    First step towards the paradigm shift of writing Set Based code:
    ________Stop thinking about what you want to do to a ROW... think, instead, of what you want to do to a COLUMN.
    "Change is inevitable... change for the better is not".

    Helpful Links:
    How to post code problems
    How to Post Performance Problems
    Create a Tally Function (fnTally)
    Intro to Tally Tables and Functions

  • Agree AND is not divion (I didnt mean divion was AND, I meant the expalantion I had written is how AND works)

    I was using the divion to convert our normal number to binary. The divion is the way humans have to do it. I am not sure of any other way

    Similarly you have to use multiplication to convert a binary to a normal number

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