January 27, 2014 at 4:00 am
Hi,
how can i get distinct Value from each column from a Table?
I think dynamic-sql is the rigth way 🙂
Foreach column in Table
Select distinct [column] from Table
next
Thanks
Nicole
January 27, 2014 at 4:54 am
Another way is to copy the run the contents of the below SELECT statement:
SELECT 'SELECT DISTINCT [' + COLUMN_NAME + '] FROM ' + TABLE_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = 'SomeTable' -- your table
---------------------------------------------------------
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Howard Zinn
January 27, 2014 at 7:42 am
Another way to get your code:SELECT 'SELECT DISTINCT ' + AC.[name] + ' AS Column_Name FROM ' + T.[name]
FROM sys.tables AS T
INNER JOIN sys.all_columns AC ON T.[object_id] = AC.[object_id]
INNER JOIN sys.types TY ON AC.[system_type_id] = TY.[system_type_id]
AND AC.[user_type_id] = TY.[user_type_id]
WHERE T.[is_ms_shipped] = 0
I think the dynamic code using sp_executesql would be helpful.
January 27, 2014 at 5:38 pm
Here's my interpretation of your requirement:
WITH SampleData (C1, C2) AS
(
SELECT 'A', 'AA'
UNION ALL SELECT 'A', 'BB'
UNION ALL SELECT 'B', 'CC'
UNION ALL SELECT 'C', 'CC'
UNION ALL SELECT 'C', 'DD'
)
SELECT Col, C
FROM
(
SELECT *, rn=ROW_NUMBER() OVER (PARTITION BY Col, C ORDER BY (SELECT NULL))
FROM SampleData a
CROSS APPLY
(
VALUES ('C1', C1),('C2', C2)
) b (Col, C)
) a
WHERE rn=1;
Please let us know if any of these responses have been helpful.
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