Data display issue

  • For a given County, I am returning the cities in that County

    SELECT DISTINCT CITY FROM DEMO WHERE COUNTY = @COUNTY

    CITY

    -----

    EDINA

    BLOOMINGTON

    EDEN PRAIRIE

    SHAKOPEE

    How do I display this data in a row like

    CITY1 CITY2 CITY3 CITY4 CITY5 CITY6

    --------------------------------------------------------------------------

    EDINA BLOOMINGTON EDEN PRAIRIE SHAKOPEE

    Thanks for great help

    C

  • Write a cursor.

    Fetch each county into it.

    Create a variable and keep concat'ing the new county + a space

    When the cursor is done, print the variable that contains the string with the individual rows

    /* ----------------------------- */
    Tochter aus Elysium, Wir betreten feuertrunken, Himmlische, dein Heiligtum!

  • Forget the cursor... try this instead.

    -- See how this starts off with a table and data in it?

    -- If you had provided us the data in this format,

    -- it would have made things easier for all of the

    -- volunteers on this site to help you out.

    DECLARE @test-2 table (Country varchar(50), City varchar(50))

    INSERT INTO @test-2

    SELECT 'USA','Washington' UNION ALL

    SELECT 'USA', 'Portland' UNION ALL

    SELECT 'USA', 'San Antonio' UNION ALL

    SELECT 'USA', 'Houston' UNION ALL

    SELECT 'USA', 'Tampa' UNION ALL

    SELECT 'USA', 'Boston'

    ;WITH CTE AS

    (

    SELECT Country,

    RowID = ROW_NUMBER() OVER (ORDER BY (SELECT 0)),

    City

    FROM @test-2

    WHERE Country = 'USA'

    )

    SELECT City1 = MAX(CASE WHEN RowID = 1 THEN CITY ELSE NULL END),

    City2 = MAX(CASE WHEN RowID = 2 THEN CITY ELSE NULL END),

    City3 = MAX(CASE WHEN RowID = 3 THEN CITY ELSE NULL END),

    City4 = MAX(CASE WHEN RowID = 4 THEN CITY ELSE NULL END),

    City5 = MAX(CASE WHEN RowID = 5 THEN CITY ELSE NULL END)

    FROM CTE

    You might want to check out this article by MVP Jeff Moden[/url] on generating dynamic cross-tab data.

    Wayne
    Microsoft Certified Master: SQL Server 2008
    Author - SQL Server T-SQL Recipes


    If you can't explain to another person how the code that you're copying from the internet works, then DON'T USE IT on a production system! After all, you will be the one supporting it!
    Links:
    For better assistance in answering your questions
    Performance Problems
    Common date/time routines
    Understanding and Using APPLY Part 1 & Part 2

  • How the heck will that work with a country like USA or Canada where you have 1000s of cities?

  • Cnu2010 (4/30/2010)


    For a given County, I am returning the cities in that County

    SELECT DISTINCT CITY FROM DEMO WHERE COUNTY = @COUNTY

    CITY

    -----

    EDINA

    BLOOMINGTON

    EDEN PRAIRIE

    SHAKOPEE

    How do I display this data in a row like

    CITY1 CITY2 CITY3 CITY4 CITY5 CITY6

    --------------------------------------------------------------------------

    EDINA BLOOMINGTON EDEN PRAIRIE SHAKOPEE

    Thanks for great help

    C

    What's the big picture of the project here? This seems like a reporting need rather than simple DML.

  • GregoryF (4/30/2010)


    Write a cursor.

    Fetch each county into it.

    Create a variable and keep concat'ing the new county + a space

    When the cursor is done, print the variable that contains the string with the individual rows

    Heh... nah... no cursors... too slow. Besides, the OP wants it in separate columns.

    --Jeff Moden


    RBAR is pronounced "ree-bar" and is a "Modenism" for Row-By-Agonizing-Row.
    First step towards the paradigm shift of writing Set Based code:
    ________Stop thinking about what you want to do to a ROW... think, instead, of what you want to do to a COLUMN.
    "Change is inevitable... change for the better is not".

    Helpful Links:
    How to post code problems
    How to Post Performance Problems
    Create a Tally Function (fnTally)
    Intro to Tally Tables and Functions

  • Ninja's_RGR'us (4/30/2010)


    How the heck will that work with a country like USA or Canada where you have 1000s of cities?

    Heh... one can only hope that the criteria presented is "example only" and would be a little tighter. 😉

    --Jeff Moden


    RBAR is pronounced "ree-bar" and is a "Modenism" for Row-By-Agonizing-Row.
    First step towards the paradigm shift of writing Set Based code:
    ________Stop thinking about what you want to do to a ROW... think, instead, of what you want to do to a COLUMN.
    "Change is inevitable... change for the better is not".

    Helpful Links:
    How to post code problems
    How to Post Performance Problems
    Create a Tally Function (fnTally)
    Intro to Tally Tables and Functions

  • Cnu2010 (4/30/2010)


    For a given County, I am returning the cities in that County

    SELECT DISTINCT CITY FROM DEMO WHERE COUNTY = @COUNTY

    CITY

    -----

    EDINA

    BLOOMINGTON

    EDEN PRAIRIE

    SHAKOPEE

    How do I display this data in a row like

    CITY1 CITY2 CITY3 CITY4 CITY5 CITY6

    --------------------------------------------------------------------------

    EDINA BLOOMINGTON EDEN PRAIRIE SHAKOPEE

    Thanks for great help

    C

    You're almost brand new to the forum... take a look at the article at the first link in my signature line below. People will trip over each other to help you with a coded example...

    --Jeff Moden


    RBAR is pronounced "ree-bar" and is a "Modenism" for Row-By-Agonizing-Row.
    First step towards the paradigm shift of writing Set Based code:
    ________Stop thinking about what you want to do to a ROW... think, instead, of what you want to do to a COLUMN.
    "Change is inevitable... change for the better is not".

    Helpful Links:
    How to post code problems
    How to Post Performance Problems
    Create a Tally Function (fnTally)
    Intro to Tally Tables and Functions

  • DECLARE @test-2

    TABLE (

    Country VARCHAR(50),

    City VARCHAR(50)

    );

    INSERT @test-2

    SELECT 'USA', 'Washington' UNION ALL

    SELECT 'USA', 'Portland' UNION ALL

    SELECT 'USA', 'San Antonio'UNION ALL

    SELECT 'USA', 'Houston' UNION ALL

    SELECT 'USA', 'Tampa' UNION ALL

    SELECT 'USA', 'Boston' UNION ALL

    SELECT 'NZ', 'Wellington' UNION ALL

    SELECT 'NZ', 'Auckland' UNION ALL

    SELECT 'NZ', 'Christchurch'UNION ALL

    SELECT 'NZ', 'Dunedin';

    SELECT P.Country,

    P.City1,

    P.City2,

    P.City3,

    P.City4,

    P.City5,

    P.City6,

    P.City7,

    P.City8,

    P.City9

    FROM (

    SELECT T.Country,

    value = T.City,

    name = 'City' + CONVERT(VARCHAR(20), ROW_NUMBER() OVER (PARTITION BY T.Country ORDER BY (SELECT 0)))

    FROM @test-2 T

    ) Source

    PIVOT (

    MAX(value)

    FOR name IN (City1, City2, City3, City4, City5, City6, City7, City8, City9)

    ) P;

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